<p>Hi I have a XML RSS Feed file and is using the XSLT style. I want to pull data from a table for the Feed and when I run the XML file it has no information just the RSS Feed style. What am I doing wrong?<br><br>Here is my codes:<br><br></p>
myData.xml<p><?xml version="1.0" encoding="utf-8" ?>
<?xml-stylesheet type="text/xsl" href="rss.xslt"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom">
<channel>
<Title>Gee Web Solutions</Title>
<link>http://www.sigar.mil/rss/</link>
<description>Watch articles from C# Corner</description>
<copyright>© 1999 - 2011 Mindcracker LLC. All Rights Reserved</copyright>
<item>
<FeedSpeeches ID="1">
<Title>Deon</Title>
<Author>Gee</Author>
<Description>Washington</Description>
<Link>http://www.sigar.mil/rss/</Link>
</FeedSpeeches>
</item>
</channel>
</rss></p><br>rss.xslt<p><?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<head>
<title>Gee Web Solutions</title>
</head>
<body>
<table cellpadding="2" cellspacing="0" border="0" width="75%">
<xsl:for-each select="FeedSpeeches">
<xsl:for-each select="rss/channel/item">
<tr style="color:#0080FF;">
<td style="text-align:left;font-weight:bold;">
<xsl:value-of select ="Title"></xsl:value-of>
</td>
<td style="text-align:right;font-weight:bold;">
<i>
<xsl:value-of select ="Author"></xsl:value-of>
</i>, <xsl:value-of select="pubDate"/>
</td>
</tr>
<tr>
<td colspan="2" style="text-align:left;padding-top:10px;">
<xsl:value-of select="Description"/>
</td>
</tr>
<tr>
<td colspan="2" style="text-align:right;">
<a href="{link}" rel="bookmark">
More...
</a>
</td>
</tr>