xml parse to class

Question

How to parse xml file with values into class file in solution? Using c# in Visual studio 2017.

Altaf Ansari · Answer

You can acheive by using following way.. first xml data into DataTable then Convert DataTable to List of Class // Conversion Xml file to DataTable public DataTable CreateDataTableXML( string XmlFile) { XmlDocument doc = new XmlDocument(); doc.Load(XmlFile); DataTable Dt = new DataTable(); try { Dt.TableName = GetTableName(XmlFile); XmlNode NodoEstructura = doc.DocumentElement.ChildNodes.Cast ().ToList()[0]; progressBar1.Maximum = NodoEstructura.ChildNodes.Count; progressBar1.Value = 0; foreach (XmlNode columna in NodoEstructura.ChildNodes) { Dt.Columns.Add(columna.Name, typeof (String)); Progress(); } XmlNode Filas = doc.DocumentElement; progressBar1.Maximum = Filas.ChildNodes.Count; progressBar1.Value = 0; foreach (XmlNode Fila in Filas.ChildNodes) { List string > Valores = Fila.ChildNodes.Cast ().ToList().Select(x => x.InnerText).ToList(); Dt.Rows.Add(Valores.ToArray()); Progress(); } } catch (Exception ex) { } return Dt; } Data Table to List of Class public List DataTableToList (DataTable table) where T : class , new () { try { List list = new List (); foreach (var row in table.AsEnumerable()) { T obj = new T(); foreach (var prop in obj.GetType().GetProperties()) { try { PropertyInfo propertyInfo = obj.GetType().GetProperty(prop.Name); propertyInfo.SetValue(obj, Convert.ChangeType(row[prop.Name], propertyInfo.PropertyType), null ); } catch { continue ; } } list.Add(obj); } return list; } catch { return null ; } }