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Answers

var filename = $('#fileData').val()

Sunil Sudhansu

Sunil Sudhansu

7y
1.2k
1
var filename = $('#fileData').val();
 
it gives like this C:\fakepath\SO_Status.xlsx
 
but what i realy wanted is path of a file and not data inside a file / no need to upload a file C:\filesFolder\SO_Status.xlsx (assuming 'SO_Status.xlsx' file present in fakepath)
 
thanks
Answers (4)