Two Forms in C#

Question

The coding relates to Visual C#.NET 2005 I have two forms (Form1 and Form2). Form2 is called by Form1 as Show() In Form1 Button-1 ----> Form2 frmform2 = new Form2(this); frmform2.Show(); Now I can switch back to form1 also without closing the Form2. I can click on the form1 also. If I click the Button-1 again in the Form1, another Form2 appears. So it makes two forms. Can I check whether the Form2 is already invoked and prevent it from appearing again? I want to activate the already opened Form2 but not a new Form2?

Brandon Lewis · Answer

In the form1 button click event handler, do this: bool formIsOpen = false ; //Iterate through all of the form instances owned by form1 foreach ( Form form in this .OwnedForms) { if (form is Form2 ) { //Set the check variable formIsOpen = true ; //Focus the form instance form.Focus(); //Break from the foreach loop break ; } } //If the form is not open if (!formIsOpen) { //Create a new instance amd show it using this //current form instance as the owner Form2 form2 = new Form2 (); form2.ShowDialog( this ); } This will only work when you create an instance of Form2, you specify that the current instance of Form1 is the owner using the form2.ShowDialog(this) line of code.

Narmada k · Answer

hi, instead of using frmform2.show() use frmform2.showdialouge();

Manuel · Answer

You should declare a variable of type Form2 in Form1 and define it with null. So you could define Form2 first time you use it by checking if it is null. After that check you jut call Show(). If Form2 is already displayed nothing happens without activating that form.