read values textbox when I create text box in aspx.cs

Question

hi guys. I have a problem with my script, I created textbox like :

"tdNilai = new TableCell();
txtNilaiRusak = new TextBox();
txtNilaiRusak.Attributes["id"] = arIdChild[b].ToString();
txtNilaiRusak.CssClass = "form-control create-number";
int dataKomponen = arIdKomponen.Count;"

but when I input values in front values always txtxNilairusak="". wht should I do. please help me soon

Manas Mohapatra · Answer

Try like below: private void CreateTextBox() { TextBox txt = new TextBox(); txt.ID = "dynaTextBox" ; pnlTextBoxes.Controls.Add(txt); // Adding textbox to panel } // Get the textbox value TextBox tb = (TextBox)pnlTextBoxes.FindControl( "dynaTextBox" ); TextBox tb = (TextBox)Page.FindControl( "dynaTextBox" ); // Getting on page if (tb != null ) { string temp = tb.Text; }

mega sarasvari · Answer

thankyou.. for help me, can you give me your What's app ? I need it for someday if I need your help again

Manas Mohapatra · Answer

Your code is not correct. Follow below URL: http://www.aspsnippets.com/Articles/Get-Value-Text-of-dynamically-created-TextBox-in-ASPNet-using-C-and-VBNet.aspx

mega sarasvari · Answer

jml child = 21 I make textboxt in table like this.txtNilaiRusak = new TextBox[JmlChild]; txt txtNilaiRusak.attributes["id"] I used arraylistId[i].tostring() look this picture I create tectbox like :

mega sarasvari · Answer

protected void btnSimpan_Click(object sender, EventArgs e) { for(int i=0;i TextBox txtselected = (TextBox)tblData.FindControl(arIdChild[i].ToString()); TextBox txtselected2 = (TextBox)Page.FindControl(arIdChild[i].ToString()); if (txtselected != null && txtselected!=null) { string temp = txtselected.Text; string temp2 = txtselected2.Text; } } this.validate(); } but result = null

Manas Mohapatra · Answer

What the error you are getting..Please provide details..

mega sarasvari · Answer

TextBox tb = (TextBox)pnlTextBoxes.FindControl( "dynaTextBox"); TextBox tb = (TextBox)Page.FindControl( "dynaTextBox") error on this. name must not same