not executing code after Task in async/await programming

Question

Hi ,

I am trying to understand the actual use of asyn/await in c# and have gone through few articles and tried with an example as below.

class Program
{
static void Main(string[] args)
{
Program p = new Program();
p.MethodOne();
p.MethodTwo();
p.MethodThree();
}
public void MethodOne()
{
Console.WriteLine("methodone has been called");
}
public async Task MethodTwo()
{
Task<string> delayingMethodCall = new Task<string>(DelayingMethod);
Console.WriteLine("methodTwo call started");
string message = await delayingMethodCall;
Console.WriteLine(message);
Console.WriteLine("methodTwo called");
Console.ReadKey();
}
public void MethodThree()
{
Console.WriteLine("methodThree has been called");
}
public string DelayingMethod()
{
System.Threading.Thread.Sleep(5000);
return "Delayed Process is done";
}
}

I am able to see third method's result , but the code after string message = await delayingMethodCall;

is not executing.

Can someone explain me the issue here?

Thanks in Advance

Ravi.

Amit Gupta · Answer

Change MethodTwo's body to the below one public async Task MethodTwo() { Task string > delayingMethodCall = new Task string >(DelayingMethod); Console.WriteLine( "methodTwo call started" ); delayingMethodCall.Start(); string message = delayingMethodCall.Result; Console.WriteLine(message); Console.WriteLine( "methodTwo called" ); Console.ReadKey(); } Reason: Didn't dig much into this but I found the issue in below await delayingMethodCall; You just called the await function without starting the Task and to get the output, you should use obj.Result. Hope your doubts were cleared. Good Luck!

Ravi Kiran Chanduri · Answer

Hi Amit, no luck even after the change

Amit Gupta · Answer

This is because, you didn't started the task, use delayingMethodCall.Start(); and inspite of using Thread.Sleep(..), use Task.Delay(..)