Hi I want to pass an array to a method which must multiply all the numbers of the array by 2 and return the new array to Main. This gives as output: System.Int32[] 5 times. Thanks static int[] mm(int[] arr1) { for (int i = 0; i arr1[i] *=2; return arr1; } static void Main() { int[] arr1 = new int[5]; Console.Write("Input the number:"); for (int j = 0; j { Console.Write("number - {0} : ", j + 1); arr1[j] = Convert.ToInt32(Console.ReadLine()); } for (int j = 0; j Console.Write(mm(arr1) + " "); }

You can pass an array by reference from a caller code and the same array variable you can use without returning it.

I found it: foreach (int i in mm(arr1)) Console.Write(i + " "); }

Answers

how to return an array from a method?

Valerie Meunier

552

Hi
I want to pass an array to a method which must multiply all the numbers of the array by 2 and return the new array to Main.
This gives as output: System.Int32[] 5 times.
Thanks

static int[] mm(int[] arr1)
{
for (int i = 0; i < arr1.Length; i++)
arr1[i] *=2;
return arr1;
}
static void Main()
{
int[] arr1 = new int[5];

Console.Write("Input the number:");
for (int j = 0; j < 5; j++)
{
Console.Write("number - {0} : ", j + 1);
arr1[j] = Convert.ToInt32(Console.ReadLine());
}

for (int j = 0; j < 5; j++)
Console.Write(mm(arr1) + " ");
}