How to print a unique elements of an Array?

Question

Anil Jha · Answer

I have seen many answeres here but all the answers are in old style but C# has grown now. By using LINQ you can achieve it in a minimal code. Try to find unique elements in array using below simple approach. class Program { static void Main( string [] args) { int [] items = { 2, 5, 7, 5, 8, 10, 8 }; IEnumerable int > uniqueItems = items.Distinct int >(); Console.WriteLine( "Unique array items: " + string .Join( "," , uniqueItems)); Console.ReadLine(); } } /* Output: Unique array items: 2, 5, 7, 8, 10 */

Serge Klokov · Answer

private static IEnumerable int > FindUniqueNumbersQuick( int [] numbers, out IEnumerable int > duplicates) { var unique = new List int >(); var dups = new List int >(); foreach (var n in numbers) { if (dups.Contains(n)) continue ; if (unique.Contains(n)) { unique.Remove(n); dups.Add(n); continue ; } unique.Add(n); } duplicates = dups; return unique; } // look full application here: // https://github.com/sergeklokov/FindUniqueNumbers/blob/master/FindUniqueNumbers/FindUniqueNumbers.cs

Manikandan Murugesan · Answer

Refer the below code to print unique elements in array: using System; public class Exercise6 { public static void Main() { int n,ctr=0; int [] arr1 = new int [100]; int i, j, k; Console.Write( "

Print all unique elements of an array:
" ); Console.Write( "------------------------------------------
" ); Console.Write( "Input the number of elements to be stored in the array :" ); n = Convert.ToInt32(Console.ReadLine()); Console.Write( "Input {0} elements in the array :
" ,n); for (i=0;i { Console.Write( "element - {0} : " ,i); arr1[i] = Convert.ToInt32(Console.ReadLine()); } /*Checking duplicate elements in the array */ Console.Write( "
The unique elements found in the array are : 
" ); for (i=0; i { ctr=0; /*Check duplicate bifore the current position and increase counter by 1 if found.*/ for (j=0; j { /*Increment the counter when the seaarch value is duplicate.*/ if (arr1[i]==arr1[j]) { ctr++; } } /*Check duplicate after the current position and increase counter by 1 if found.*/ for (k=i+1; k { /*Increment the counter when the seaarch value is duplicate.*/ if (arr1[i]==arr1[k]) { ctr++; } } /*Print the value of the current position of the array as unique value when counter remain contains its initial value.*/ if (ctr==0) { Console.Write( "{0} " ,arr1[i]); } } Console.Write( "

" ); } }

Naveen Arumugam · Answer

can you explain with C# Program using foreach statement to print an unique array.Thank You...

Sundaram Subramanian · Answer

#include #include using namespace std; void printDistinct(int arr[], int n) { // Pick all elements one by one for (int i=0; i { // Check if the picked element is already printed int j; for (j=0; j if (arr[i] == arr[j]) break; // If not printed earlier, then print it if (i == j) cout } } // Driver program to test above function int main() { int arr[] = {6, 10, 5, 4, 9, 120, 4, 6, 10}; int n = sizeof(arr)/sizeof(arr[0]); printDistinct(arr, n); return 0; } Run on IDE

Rajkiran Swain · Answer

/* * C program to print all unique elements of an unsorted array */ #include #include int main() { int array[100], size, i, j; printf( "Enter number of elements in array
" ); scanf( "%d" , &size); printf( "Enter %d numbers
" , size); for (i = 0; i scanf( "%d" , &array[i]); } printf( "Unique Elements
" ); for (i = 0; i for (j=0; j if (array[i] == array[j]) break ; } if (i == j){ /* No duplicate element found between index 0 to i */ printf( "%d " , array[i]); } } getch(); return 0; }