How to open page with jquery

Question

Hi, I have this script @*$.ajax({ type: 'GET', data: { id : StoreID}, url: '@Url.Action("Create")', contentType: 'apllication/html; charset=utf-8', success: function () { //window.open(@Url.Action("Create", "Storebranch") ) } })* now I would like to know what to put on the success part to open the page. I have use windows.location.href but it is not working as expected as I have a double call to the controller which nullify my parameter on the second call. P.S. Moderator if you have to delete my script please let me know the right way to post it, excuse me if I am doing it the wrong way.

Schleid Alex · Answer

Not working posting a sample again $.ajax({ type: 'GET', data: { id : StoreID}, url: '@Url.Action("Create")', contentType: 'apllication/html; charset=utf-8', success: function (data) { @Url.Action("Create","StoreBranch", new { id = data}) } }) Now I have compilation error

Jignesh Kumar · Answer

Hi Alex, In your code you are passing url and from sucess also url. Please check link below I have shared just you need to pass url in sucess call. $.ajax({ type: 'GET' , data: { id: StoreID }, url: '@Url.Action("Create", "StoreBranch")' ;, contentType: 'apllication/html; charset=utf-8' , success: function (data) { window.location.href = data.redirecturl; } });

Schleid Alex · Answer

Thank you I took a look at it but not my typical scenarion in my case I have a variable in jquery that I want to send to the controller action create and open the create wiew. the script does all the thing right for now. I just don't know what to put on success to call the controller without having it called twice. Thank you!

Jignesh Kumar · Answer

please try this one, https://forums.asp.net/t/1971380.aspx?how+to+call+controller+action+on+ajax+success+