How to get int math.random round number?

Question

Hi,

Let's say, if I want to set Math.random(); in variable.

'idPartnerProject' model class object, some times it will cotain integer also,

foreach (var partnerProjecttemp in pageVM.Form5.Projects)
{
partnerProjectBL.idPartnerProject = Convert.ToInt32(partnerProjecttemp.idPartnerProject);
/*if idPartnerProject id existing then update record, not exist add a new record*/
}

And,

But now error raising, Input string was not in a correct format.

How can I solve this?

Nitin Sontakke · Answer

Yes, it will. But now you have the integer part. And you do something as follows: float d = 0.972283766387763F; float x = d * 1000; int y = Convert.ToInt32(x); DO NOT COPY AND PASTE ABOVE CODE. Please give meaningful variable names. I was lazy to type meaningful names. This is for demonstration purpose only.

Nitin Sontakke · Answer

Why not multiply the result by 100 or 1000 depending on how many digits integer you want?

Nitin Sontakke · Answer

Dear Abhilash, these are all very minor things! If it is string, can you not use float.Parse() method to get float? Is this someone else's code? Have you written class with that property? Why that property is String in first place? Think from all the angles and resolve. You can add some minor check to check if it is zero and stuff like that.

Asma Khalid · Answer

Do as follow i.e. int value = Convert.ToInt32(Math.Round(Math.Random)); partnerProjectBL.idPartnerProject = value;

Abhilash J A · Answer

Excuse me Nitin Sir, the 'idPartnerProject' is being string datatype Then, how can I solve the error? partnerProjectBL.idPartnerProject = Convert.ToInt32(partnerProjecttemp.idPartnerProject); OR If random number is coming, that is the id not existing in db. Then 'partnerProjectBL.idPartnerProject = 0' return zero. How can I do this?

Abhilash J A · Answer

Hello Nitin Sir, Still it 'idPartnerProject' holding decimal number.