I have simple List . I need to define Table that each column of this table is one of this list elements. So i will use ListView - I need to define a ListView that each column of this ListView is one of my List => that mean that the first column name is List [0] second column name is List [1] . . . I can't fine any way to do it. I google it and all the examples are shown how to create dynamic rows Any help please ...

Answer

how to defind dynamic column of this table ( ListView ) ?

Yanshof

716

I have simple List<string>.
I need to define Table that each column of this table is one of this list elements.

So i will use ListView - I need to define a ListView that each column of this ListView is one of my List<string> => that mean that the

first column name is List<string>[0]
second column name is List<string>[1]
.
.
.

I can't fine any way to do it.
I google it and all the examples are shown how to create dynamic rows

Any help please ...