How to assign actions to links that are in datagridview c#

Question

Hi friends I have in datagrid view 3 hypertext links in each lines I have links with other records and I want when I select a line and I click on one of these three links it shows me a messagebox for example

Madhanmohan Devarajan · Answer

Here is the code to show another form based on the value in the DataGridView selected cell. You need to create another form (form2) and will be displayed on clicking the cell that contains values in the If condition. Please change the new form name in the code accordingly. private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e) { if (dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value != null) { string cellval = dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.ToString(); if (cellval.Contains ("google")) { Form2 frm = new Form2 (this); frm.Show(); } } } Please accept this answer, if it is helpful to you. Also it will be helpful for others who are searching for similar kind of requirement.

ma ouml · Answer

Madhanmohan Devarajan thank you so much Mr

ma ouml · Answer

Madhanmohan Devarajan Yes now it works I want for each link when I click it shows me another winforms How to do please

Madhanmohan Devarajan · Answer

Please try this, it worked for me. private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e) { if (dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value != null) { MessageBox.Show(dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.ToString()); } }

ma ouml · Answer

Ravi Sangtani This solution works just with the first column but the other links do not work

Ravi Sangtani · Answer

Try this one You have to press shift key when you click on selected row cell try { MessageBox.Show(dataGridView1.SelectedRows[0].Cells[e.ColumnIndex].Value.ToString()); } catch (Exception) { }

ma ouml · Answer

Ravi Sangtani

Ravi Sangtani · Answer

Hello ma oumi, I think bellow code may help you. you have to add datagridview cell click event. private void dataGridView1_CellClick(object sender, DataGridViewCellEventArgs e) { MessageBox.Show(dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.toString()); }

Madhanmohan Devarajan · Answer

Please go through the below link, that tells you how to bind objects to Datagridview. http://www.c-sharpcorner.com/article/bind-objects-to-a-datagridview-control/

ma ouml · Answer

In any case I want an answer on the question I asked

Madhanmohan Devarajan · Answer

ADO.NET: http://msdn2.microsoft.com/en-us/library/h43ks021(VS.71).aspx ASP.NET: http://msdn2.microsoft.com/en-us/asp.net/default.aspx Please see the two links above. Briefly, asp.net is Microsoft's framework for building websites and web services, while ado.net is a set of components for accessing and manipulating data, primarily targeted at relational databases. http://www.c-sharpcorner.com/uploadfile/puranindia/what-is-ado-net/ DataGridView comes under ASP.NET because it is a control used in the User Interface. Also go through the below link to understand about all the grids available in ASP.NET and DataGridView is listed under ASP.NET framework. http://codehunters.in/difference-between-listview-gridview-and-datagridview-asp-net/

ma ouml · Answer

No it is not asp .net I tell you that c # (ado.net) And more reason I said datagridview I did not say grid view

Madhanmohan Devarajan · Answer

The code i have sent is ASP.NET control (Datagrid View) for ASPX page, First i would like to know whether you are working in ASP.NET with C#. Because ADO.NET is the framework for connecting DataSource. But your question is related to ASP.NET User Interface.

ma ouml · Answer

Madhanmohan Devarajan No it is in ado.net it is not asp

Madhanmohan Devarajan · Answer

Here is the template for the gridview with link "GridView01" runat= "server" EnableModelValidation= "True" > "Code" HtmlEncode= "False" DataFormatString= " Your Link Text Goes here " />

ma ouml · Answer

Ravi Sangtani Thank you i will try it

ma ouml · Answer

I'm sorry but the answer you posted does not meet my problem

ma ouml · Answer

thank you