How do I kill a process I use to show an image file?

Question

Process proc=null;//declaration at top of windows form code

proc = Process.Start(imagefilename);

if (proc != null) proc.Kill();

but proc is always null.

if I use proc = new Process(); proc.StartInfo.FileName=imagefilename; proc.Start(); proc.Kill()//after image showing. gives no process associate error. Help! I am using VS 2012 Express because I have to use and create Windows Forms and newer version don't support that well or at all.

Tuhin Paul · Answer

ProcessStartInfo startInfo = new ProcessStartInfo(imagefilename); Process imageProcess = Process.Start(startInfo); if (imageProcess != null) { imageProcess.WaitForExit(); // wait for the process to exit imageProcess.Dispose(); // dispose of the process resources } we use ProcessStartInfo to create a new process and specify the file name of the image to be displayed. Then we start the process using Process.Start() and store the returned Process object in a variable imageProcess.

Naimish Makwana · Answer

Try below, Process process = Process.Start("imagefilename.jpg"); if (process != null) { process.WaitForInputIdle(); // wait for the process to become idle process.Kill(); // kill the process } Thanks

Jon Jacobs · Answer

Whenever I use proc.Kill(); I get: "No process is associated with this object." I think I get what is happening. As soon as the Windows Photo Viewer is launched by proc.Start, the process immediately exits. So what I really need is a way to find the Windows Photo Viewer instance and kill it. In a run of my program, I will have launched dozens of images, so I need to be able to kill the current one before launching the next one.

Tuhin Paul · Answer

To kill a process that displays an image file, you first need to start the process using Process.Start() and then obtain the process handle to kill it.

Jon Jacobs · Answer

How do I kill a process by its handle? the Kill method doesn't take parameters.

Jon Jacobs · Answer

Thank you. Process proc = Process.Start(startInfo); ALWAYS returns null for me. So I will experiment with: ProcessStartInfo startinfo = new ProcessStartInfo(imagefilename); proc = new Process(); proc.StartInfo = startinfo; proc.Start(); handle = proc.Handle;