@foreach (var item in Model) {

Question

Server Error in '/' Application. Object reference not set to an instance of an object. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.NullReferenceException: Object reference not set to an instance of an object. Source Error: Line 27: Line 28: Line 29: @foreach (var item in Model) { Line 30: Line 31: Please Help me out in this

Dorababu Meka · Answer

Can you change your return view as follows return View(employees);

Ranjit Powar · Answer

In action method create list of employee as List lst=new List Add employees in lst and then return from view return View(lst);; On View @model List

Ateeq Atiq Ali Khan · Answer

put the entire code in if loop @if(Model!=null){foreach (var item in Model)}

Amit Kumar · Answer

Hi dear, Firstly check the model count if model count then bind use code like.. @if (Model.Count != 0) { //Write your code here....... }

Zafar Iqbal · Answer

Thank you so much sir for your efforts you put in solving my problem .I got my issue resolved

Zafar Iqbal · Answer

Sir i am uploading the source code also and here the controller also on this view in which i am getting the error you please help me out in this case using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using BusinessLayer; namespace MVCDemo.Controllers { public class EmployeeController : Controller { // GET: Employee public ActionResult Index() { EmployeeBusinessLayer employeeBusinessLayer = new EmployeeBusinessLayer(); List employees = employeeBusinessLayer.Employees.ToList(); return View(); } } }

Dorababu Meka · Answer

This is how your controller should be [HttpGet] public ActionResult Index() { var employees= new List (); //Model employees.Add(new Employee { Name = "XYZ", Gender = "Male }); employee.Add(new Employee { Name = "ABC", Gender = "Male }); return View(employees); }

Dorababu Meka · Answer

You are showing the Model but not the controller you are binding. Can you post your controller code that you are binding to the view

Zafar Iqbal · Answer

using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace BusinessLayer { public class Employee { public int ID { get; set; } public string Name { get; set; } public string Gender { get; set; } public string City { get; set; } public DateTime DateOfBirth { get; set; } } }

Zafar Iqbal · Answer

Done it also but still the same error msg

Dorababu Meka · Answer

Does your BusinessLayer.Employee is returning list of employees? can you show us your controller code

Zafar Iqbal · Answer

Still not working as i have bind also

Zafar Iqbal · Answer

@model IEnumerable @{ ViewBag.Title = "Index"; } Index @Html.ActionLink("Create New","Create") @Html.DisplayNameFor(model =>model.Name) @Html.DisplayNameFor(model => model.Gender) @Html.DisplayNameFor(model => model.City) @Html.DisplayNameFor(model => model.DateOfBirth) If ( Model != null ) { @foreach (var item in Model) { @Html.DisplayFor(modelItem => item.Name) @Html.DisplayFor(modelItem => item.Gender) @Html.DisplayFor(modelItem => item.City) @Html.DisplayFor(modelItem => item.DateOfBirth) @Html.ActionLink("Edit", "Edit", new { id=item.ID }) | @Html.ActionLink("Details", "Details", new { id=item.ID }) | @Html.ActionLink("Delete", "Delete", new { id=item.ID }) } }

Ranjit Powar · Answer

How do you pass list of model?

Dorababu Meka · Answer

Can you share the screen shot of your Model, if your model is null then you should have a condition check like @if (Model!=null) { // bind your table here }

Zafar Iqbal · Answer

No Sir , holding data check whether it is null but how i can do it.?

Dorababu Meka · Answer

Does ur model is holding data check whether it is null

Ranjit Powar · Answer

Change your action as namespace MVCDemo.Controllers { public class EmployeeController : Controller { // GET: Employee public ActionResult Index() { EmployeeBusinessLayer employeeBusinessLayer = new EmployeeBusinessLayer(); List employees = employeeBusinessLayer.Employees.ToList(); return View( employees ); } } }