Find third largest integer in an array using only one loop?

Question

The user will input an unsorted integer array and the method should find the third largest integer in the array. input: 3 6 9 8 0

Jignesh Kumar · Answer

Please check below one int largestNumberAtPosion = 3; int[] intArray = { 3 6 9 8 0 }; var sortedArray = intArray.OrderByDescending(x => x); var topNumber = sortedArray.Skip(largestNumberAtPosion - 1).Take(1).FirstOrDefault();

Amit Mohanty · Answer

Try this int[] array = { 3 6 9 8 0 }; Array.Sort(array); int elementCount = 0; int? thirdLargestNumber = null; foreach (var element in array) { var temp = array.Skip(elementCount).ToArray(); if (temp.Length == 3) { thirdLargestNumber = temp[0]; break; } elementCount++; } Console.WriteLine($Third largest number = {thirdLargestNumber});

Aravind Govindaraj · Answer

Pls follow the steps 1.get it as list 2. Sort it as descending using lambda 3. Then apply Skip(2).Take(1) => It will skip 01 index and take 2 index value. 4. Another option after skip apply firstordefaultvaule. Both yield the same result

Uday Dodiya · Answer

public class ThirdLargestInArrayExample{ public static int getThirdLargest(int[] a int total){ int temp; for (int i = 0; i a[j]) { temp = a[i]; a[i] = a[j]; a[j] = temp; } } } return a[total-3]; } public static void main(String args[]){ int c[]={36980}; int a[]={125632}; int b[]={44669977332255}; System.out.println(Third Largest: +getThirdLargest(c5)); System.out.println(Third Largest: +getThirdLargest(a6)); System.out.println(Third Largest: +getThirdLargest(b7)); }} Output : Third Largest:6 Third Largest:3 Third Largest:66

Vishal Yelve · Answer

Try this public class Program { public static void Main() { int[] unsortedArray = new int[5] {3 6 9 8 0}; Console.WriteLine(Input UnSorted Array: ); Console.WriteLine(------------------------------------------------ ); for( int i = 0; i