Find leader in array in c#

Question

Brijesh Rathor · Answer

you can do like this public class LeadersInArray { static void findTheLeaders(int inputArray[]) { System.out.println("The leaders in "+Arrays.toString(inputArray)+" are :"); for (int i = 0; i { boolean flag = true; for (int j = i+1; j { if (inputArray[j] > inputArray[i]) { flag = false; break; } } if (flag) { System.out.println(inputArray[i]); } } } public static void main(String[] args) { findTheLeaders(new int[] {12, 9, 7, 14, 8, 6, 3}); findTheLeaders(new int[] {8, 23, 19, 21, 15, 6, 11}); findTheLeaders(new int[] {55, 67, 71, 57, 51, 63, 38}); findTheLeaders(new int[] {21, 58, 44, 14, 51, 36, 23}); } }

Mayank · Answer

#include using namespace std; /*C++ Function to print leaders in an array */ void printLeaders(int arr[], int size) { for (int i = 0; i { int j; for (j = i+1; j { if (arr[i] break; } if (j == size) // the loop didn't break cout } } /* Driver program to test above function */ int main() { int arr[] = {16, 17, 4, 3, 5, 2}; int n = sizeof(arr)/sizeof(arr[0]); printLeaders(arr, n); return 0; } I u think it resolve your query please mark as answer.

John · Answer

void printLeaders( int arr[], int size) { for ( int i = 0; i { int j; for (j = i+1; j { if (arr[i] break ; } if (j == size) // the loop didn't break console.write arr[i] ; } }