error in return view MVC

Question

i have this controller : public ActionResult search( int ? page, string search , string KEYWORD_NAME) { if (search == null ) { Bindkeyword(); return View(); } else { KEYWORD_NAME = Request.QueryString[ "Contant.KEYWORD_NAME" ]; Bindkeyword(); DataSet dst = new DataSet(); dst.Tables.Add(op.search(search, KEYWORD_NAME)); List seaech = new List (); foreach (DataRow dr in dst.Tables[0].Rows) { ContantViewModel u = new ContantViewModel(); u.articalname = dr[ "ARTICAL_NAME" ].ToString(); u.articalbody = dr[ "ARTICALBODY" ].ToString(); u.userName = dr[ "IUSER" ].ToString(); u.articlid = dr[ "ARTICL_ID" ].ToString(); seaech.Add(u); } if (seaech.Count > 0) { op.addsearch(search, KEYWORD_NAME); return View(seaech.ToPagedList(page ?? 1, 10)); } else { ContantViewModel u = new ContantViewModel(); u.s = "there is no data " ; u.s1 = "e.jpg" ; seaech.Add(u); return View(seaech.ToPagedList(page ?? 1, 10)); } } } and this is the view i use this model :@model Wiki_Reach_Site.Models.ContantViewModel i have error in the line in BOLD this is the error System.InvalidOperationException: The model item passed into the dictionary is of type 'PagedList.PagedList`1[Wiki_Reach_Site.Models.ContantViewModel]', but this dictionary requires a model item of type 'Wiki_Reach_Site.Models.ContantViewModel'. how i can fix it ?

Sachin Singh · Answer

the error is self explanatory you are passing Model of type PagedList.PagedList1 while your View is strongly typed with Wiki_Reach_Site.Models.ContantViewModel. do something like below public class MyViewModel { public PagedList.IPagedList ConstantVM { get ; set ; } } // in Action MyViewModel vm= new MyViewModel(); vm.ConstntantVM=ConstantViewModel.ToPagedList(pageNumber, PageSize); return View(vm);

Junaid Musla · Answer

Hi, Try to figure out wether your view need to have a model of type PagedList or simply just Wiki_Reach_Site.Models.ContantViewModel. While, as per your code it seems to me that your view need a model of type PagedList i.e, (collection of viewModel). So, set your view's model as below or add following in your view: @ using PagedList @model IPagedList thats it.

أماني مفيد · Answer

i added this in view @using PagedList; @using PagedList.Mvc; @model Wiki_Reach_Site.Models.ContantViewModel the ContantViewModel have 2 model iside it public class ContantViewModel { public PagedList.IPagedList Items { get; set; } public Wiki_Reach_Site.Models.Contant Contant { get; set; } } because in my view i need both

Sachin Singh · Answer

Are you sure your ContantViewModel is an IEnummerable .It must return a list of thing then only Pagination will work.

أماني مفيد · Answer

i already imported it here using PagedList; using System; using System.Collections.Generic; using System.Configuration; using System.Data; using System.Data.OracleClient; using System.Globalization; using System.Threading; using System.Web; using System.Web.Mvc; using Wiki_Reach_Site.Models; namespace Wiki_Reach_Site.Controllers { public class HomeController : Controller {

Sachin Singh · Answer

please import Pagedlist using PagedList;

أماني مفيد · Answer

my own model is ContantViewModel not ConstantViewModel i chnage it to ContantViewModel but give that ContantViewModel dose not contain defination for ToPagedList

Sachin Singh · Answer

I updated the code , and ConstantViewModel is your own viewmodel , you have successfully used it in your project so how can you get error of "doesn't exist", if you have propery imported the namespace then you shouldn't get any error.

أماني مفيد · Answer

give me error , that ConstantViewModel not exist MyViewModel vm= new MyViewModel(); vm.ConstntantViewModel=ConstantViewModel .ToPagedList(pageNumber, PageSize);