csharp fibonacci sequence

Question

Can anyone provide me the logic to print fibonacci sequence with in the given range i.e for example lower range:10 and upper range:200 the output must be:13,21,34,55,89,144

Amit Kumar Singh · Answer

Hey, static void Main(string[] args) { int lim_low,lim_up; int a = 0; int b = 1; int c; Console.WriteLine("Enter first Value"); lim_low = Convert.ToInt32(Console.ReadLine()); Console.WriteLine("Enter Last Value"); lim_up = Convert.ToInt32(Console.ReadLine()); while (a { if (a > lim_low) Console.WriteLine(a); c = a + b; a = b; b = c; } Console.ReadLine(); } If u got answer then accept my answer

Rajeev Punhani · Answer

Hi Yalavarthi, Please see the below code. class Program { static void Main(string[] args) { Program p = new Program(); int lower=Convert.ToInt16(Console.ReadLine()); int upper = Convert.ToInt16(Console.ReadLine()); Fibonacci( lower, upper); Console.ReadKey(); } public static void Fibonacci(int lower,int upper) { int a = 0; int b = 1; while(b { int temp = a; a = b; b = temp + b; if(a>lower) Console.WriteLine(a); } } } If the above solution is helpful then, accept the answer.

Amit Kumar Singh · Answer

hey, using System; namespace Fibonaccinumber { class Program { static void Main(string[] args) { int a=0; // assigning initaial value for first varible int b=1; // assigning initaial value for second varible int c=1; // assigning initaial value for third varible Console.WriteLine(a); Console.WriteLine(b); while (true) { c = a + b; if (c >= 200) { break; } Console.WriteLine(c); a = b; b = c; } Console.Read(); // to keep windows screen after running } } }

Amit Kumar Singh · Answer

Hey , Accept this answer as Correct

Y G · Answer

Thank you........

Y G · Answer

I 'm sorry to say that my requirement I will pass the lower limit and 10 and the upper limit as 200 then the output must be 13, 21, 34, 55, 89, 144 i.e, it shout not display 0,1,1,2,3,5,8