Combining array elements

Question

I want to combine 2 consecutive elements of the even str array to create another string array with output as shown in example For example if we have 6 elements in an array like string [] str = new string [] { "a" , "b" , "c" , "d" , "e" , "1" } it will combine in another string array strCombined to show output of {"ab", "cd", "e1"} Please advise on how this can be done?

Shivangi Rajde · Answer

@Ram I don't think you need to know the length of the array priorly because we are checking the length of the array dynamically. As far as the length of the strCombine variable, we don't need to have the length of the array in which we are gonna push the combined values. The logic that we have used is: we check the length of the str array, if it has even number of items then we proceed to combine the items. If it doesn't have even number of items for now we just print a message in the console. If the number of items is even we concat the item with current index -1 and item with the current index. And then we push that string into the strCombine array. Let me know if you have any other issues or if there is any missing point in the explanation.

Jignesh Kumar · Answer

Hi Ram, You can use this linq which has generic solution, https://stackoverflow.com/questions/35327255/c-sharp-linq-select-two-consecutive-items-at-once

Shivangi Rajde · Answer

You can use the code snippets below to implement the requirement. Firstly, I have checked whether there are even number of items in the array or not. If so, I have stored the string values in an array and used an empty array to push the combined values into that. tempSTR variable is used for temporarily storing the combined values. Code snippet in JavaScript You can check this code by pasting this code console to get the results. The variable strCombine will be holding the expected values. str = [ "a" , "b" , "c" , "d" , "e" , "1" ] strCombine = [] tempSTR = "" ; if (str.length % 2 == 0){ str.forEach((value, index)=>{ // console.log(value); if (index % 2 != 0){ tempSTR = str[index-1] + str[index]; // console.log(tempSTR); strCombine.push(tempSTR); } }) console.log( "Final Array:" , strCombine); } else { console.log( "Odd number of items in array" ); } Code snippet in c# string [] str = new string [] { "a" , "b" , "c" , "d" , "e" , "1" } string [] strCombine = new string []; string tempSTR = "" ; if (str.length % 2 == 0){ for (i=0;i if (index % 2 != 0){ tempSTR = str[index-1] + str[index]; strCombine.push(tempSTR); } } } else { Console.WriteLine( "Odd number of items in array" ); } Hope this helps!

Laxmidhar Sahoo · Answer

private static void combinestringarray() { string [] str = new string [] { "a" , "b" , "c" , "d" , "e" , "1" }; string [] strCombine = new string [3]; for ( int i = 0, j = 0; i { strCombine[j] = String.Concat(str[i], str[i + 1]); Console.WriteLine(strCombine[j]); } }

Ram Prasad · Answer

@Shivangi Thanks for taking your time to help me with my question. I do not know the array size as that is dependent upon the input provided by the user and length of str array string[] strCombine = new string[]; How can I bypass requirement of putting an array size?? Please advise.