Cannot sent Post multipart/form-data Httpclient c# API

Question

I am trying to send by converting string feed XML to stream multipart/form-data but getting bad request as response. Please suggest correct way to post multipart/form-data as XML or text file data sample code: public async Task string > PostAPICall( string feed, string clientID, string clientSecret) { try { HttpClient client = new HttpClient(); string uri = Constants.ApiUrl + "v3/feeds?feedType=item&setupType=byMatch" ; string token = await _authentication.GetToken(clientID, clientSecret); client.DefaultRequestHeaders.Authorization = new System.Net.Http.Headers.AuthenticationHeaderValue( "Basic" , Convert.ToBase64String(Encoding.ASCII.GetBytes(clientID + ":" + clientSecret))); client.DefaultRequestHeaders.Accept.Add( new MediaTypeWithQualityHeaderValue( "application/json" )); client.DefaultRequestHeaders.Add( "WM_SEC.ACCESS_TOKEN" , token ); client.DefaultRequestHeaders.Add( "WM_SVC.NAME" , "XXXXXXXXX" ); client.DefaultRequestHeaders.Add( "WM_QOS.CORRELATION_ID" , System.Guid.NewGuid().ToString()); //any random ID client.DefaultRequestHeaders.Add( "WM_SVC.VERSION" , "1.0.0" ); HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, uri); MultipartFormDataContent form = new MultipartFormDataContent(); HttpContent content = new StringContent( "fileToUpload" ); form.Add(content, "fileToUpload" ); /*convert string to stream*/ byte [] byteArray = Encoding.ASCII.GetBytes(feed); MemoryStream stream = new MemoryStream(byteArray); content = new StreamContent(stream); content.Headers.ContentDisposition = new ContentDispositionHeaderValue( "form-data" ) { Name = "feeds" , FileName = "feeds.xml" }; form.Add(content); string result = string .Empty; var response = client.PostAsync(uri, form).Result; if (response.StatusCode == System.Net.HttpStatusCode.OK) { result = await response.Content.ReadAsStringAsync(); } return result; } catch (Exception e) { throw e; } }

P K · Answer

Issue got fixed pass multformdata content as given below and remove line no. 14 to 27 and rest code same: var binaryContent = new ByteArrayContent(byteArray); var form= new MultipartFormDataContent(); form.Add(binaryContent, "FEEDS.XML");