Can we used return type in static method in c#

Question

Static void add(int x, int y) { return 10+20; }

Amit Kumar Singh · Answer

Hi, Yes, in your example void is return type. void will going to return nothing. static methods can be defined using the static keyword before a return type and after an access modifier Regards, Amit

Rajanikant Hawaldar · Answer

yes we can, refer below example, using System; namespace ArithmeticOperation { class Program { private delegate double Operation(double num1, double num2); private static void Main(string[] args) { Console.Write("Input number 1: "); var num1 = double.Parse(Console.ReadLine()); Console.Write("Input number 2: "); var num2 = double.Parse(Console.ReadLine()); Console.Write("Input operation (+,*,/,- or max): "); var op = Console.ReadLine().Trim(); Operation operation; switch (op) { case "+": operation = ArithmeticOperation.AddNumbers; break; case "*": operation = ArithmeticOperation.MultiplyNumbers; break; case "/": operation = ArithmeticOperation.DivideNumbers; break; case "-": operation = ArithmeticOperation.SubtractNumbers; break; case "max": operation = ArithmeticOperation.FindMaxNumber; break; default: Console.WriteLine("Error: operation is no supported"); return; } var result = operation(num1, num2); Console.WriteLine($"Result: {result}"); } } public class ArithmeticOperation { public static double AddNumbers(double num1, double num2) => num1 + num2; public static double MultiplyNumbers(double num1, double num2) => num1 * num2; public static double DivideNumbers(double num1, double num2) => num1 / num2; public static double SubtractNumbers(double num1, double num2) => num1 - num2; public static double FindMaxNumber(double num1, double num2) => num1 >= num2 ? num1 : num2; } }