Array comparison in jquery

Question

hi team please help me on below item: we have 2 arrays with some values array1 = {11345467}; array2 = {446711456}; here need to compare the 2 arrays irrespective of their position... if any value are common then need to throw true/false please help me

Vishal Joshi · Answer

Hello Murali Please check out the below code to intersect the array and find common. if there are common values it will return true or false. var array1 = [1 2 3 4] array2 = [4 5 6]; $.arrayIntersect = function(a b) { return $.grep(a function(i) { return $.inArray(i b) > -1; }); }; let existValues = $.arrayIntersect(array1 array2).length > 0; window.console && console.log(existValues); Thanks Vishal Joshi

Naimish Makwana · Answer

Try below // Define the two arrays const array1 = [11 34 54 67]; const array2 = [44 67 11 456]; // Create a function to check for common elements function haveCommonElements(arr1 arr2) { const set1 = new Set(arr1); for (const item of arr2) { if (set1.has(item)) { return true; // If a common element is found return true } } return false; // If no common elements are found return false } // Check if there are common elements const hasCommonElements = haveCommonElements(array1 array2); // Output the result console.log(hasCommonElements); Thanks

Amit Mohanty · Answer

$(document).ready(function () { var array1 = [11 34 54 67]; var array2 = [44 67 11 456]; function haveCommonValues(arr1 arr2) { return arr1.some(value => arr2.includes(value)); } var commonValuesExist = haveCommonValues(array1 array2); console.log(commonValuesExist); });