Add extra bracktes.

Question

Hello everyone I have parse static string using this JObject.Parse(data) but it's add extra brackets .

Muhammad Imran Ansari · Answer

You can also do this without Regex. like: string data2 = json.Replace( "
" , "" ); string finaldata = data2.Replace( """ , "" ); An other way to deserialize your object is write a class and use JsonConvert calls to deserializeobject. like: public class Root { public List attendee { get ; set ; } } public class Attendee { public string attendeeEmail { get ; set ; } public string attendeeName { get ; set ; } public string attendeePhone { get ; set ; } } var data = "{"attendee":[{"attendeeEmail":"apps@gmail.com","attendeeName":"Token","attendeePhone":"12345678"},{"attendeeEmail":"appsol@gmail.com","attendeeName":"Arnab","attendeePhone":"6483652"}]}" ; var finalData = JsonConvert.DeserializeObject (data);

Rohan · Answer

RuntimeBinderException: The best overloaded method match for 'System.Text.RegularExpressions.Regex.Replace(string, string, string)' has some invalid arguments This error showing

Muhammad Imran Ansari · Answer

You can remove 
 with following code: string data2 = Regex.Replace(json, "
" , "" ); string finaldata = Regex.Replace(data2, """ , "" );

Rohan · Answer

I have faced this same problem and I have use .tostring it's add extra code "{
 "publResult": [
 {
 "key": {
 "Term": "flower"
 },
 "data": [
 {
 "PublImgUrl": "https://picsum.photos/200/300.jpg",
 "Name": "Jhon",
 "Title": "owershop",
 "Description": "Online"
 },
 {
 "PublImgUrl": "https://picsum.photos/200/300.jpg",
 "Name": "JhonCena",
 "Title": "weddings",
 "Description": "FLOWERS"
 }
 ]
 },
 {
 "key": {
 "Term": "Pizza"
 },
 "data": [
 {
 "PublImgUrl": "https://picsum.photos/200/300.jpg",
 "Name": "Harry",
 "Title": "benny",
 "Description": "TAMELAC"
 },
 {
 "PublImgUrl": "https://picsum.photos/200/300.jpg",
 "Name": "Roma",
 "Title": "benny",
 "Description": "Michelle"
 }
 ]
 }
 ]
}"

Muhammad Imran Ansari · Answer

You cant remove the doubly braces as thats how json is represented in a JObject and its default behaviour. You can use Jobject().Tostring() like: var data = "{\"attendee\":[{\"attendeeEmail\":\"apps@gmail.com\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"appsol@gmail.com\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}" ; dynamic json = JObject.Parse(data).ToString(); Output: { "attendee" : [ { "attendeeEmail" : "apps@gmail.com" , "attendeeName" : "Token" , "attendeePhone" : "12345678" }, { "attendeeEmail" : "appsol@gmail.com" , "attendeeName" : "Arnab" , "attendeePhone" : "6483652" } ] }

Rohan · Answer

Muhammad Imran Ansari I have used this dynamic json = JObject.Parse(data).ToString(); It's again convert this string.

Rohan · Answer

Please any help me. Very argent this for me

Rohan · Answer

okay let me check this bro

Ankush Verma · Answer

This is my code var data = "{\"attendee\":[{\"attendeeEmail\":\"apps@gmail.com\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"appsol@gmail.com\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}"; dynamic json = JObject.Parse(data); After parse this data . "{{\"attendee\":[{\"attendeeEmail\":\"apps@gmail.com\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"appsol@gmail.com\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}}"; Add extra brackets